Solving for Distance of a Rotating Wheel

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A wheel with a diameter of 31.8 cm accelerates from 242 rpm to 380 rpm over 7.66 seconds, prompting a calculation of the distance traveled by a point on its edge. The relevant equations include angular displacement and angular velocity, which require conversion from rpm to radians per second. The user initially miscalculated the distance due to unit conversion errors but identified the mistake after clarification on using SI units. The correct approach involves calculating angular acceleration and then applying it to find the total angular displacement. Proper unit conversion is crucial for accurate results in rotational motion problems.
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Homework Statement



A wheel 31.8 cm in diameter accelerates uniformly from 242 rpm to 380 rpm in 7.66 s. How far will a point on the edge of the wheel have traveled in this time?


Homework Equations



angle = initial angle +angular velocity(t) + .5(angular acceleration)(t)

w=initial angular velocity +angular acceleration (t)

and s=R*angle

The Attempt at a Solution



i tried plugging into the equations but i really don't know what to do
 
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angle = initial angle +angular velocity(t) + .5(angular acceleration)(t)
Not quite.

θ = θo + ω*t + 1/2*α*t2

Where θ is in radians.

And there are 2π radians in a revolution.

First convert your ω's to radians/sec from rpm and figure α and then you can figure your θ.

To find distance ... x = θ *r
 
I converted to rad/sec so its 25.34 and 39.79
I found a = (39.79-25.32)/7.66 =1.886
then I used θ = θo + ω*t + 1/2*α*t2
and did θ = 0 + 25.34*7.66 + 1/2*1.886*7.66 = 249.435

So i got x=θR = 249.435(15.9) = 3966.01

But this is wrong, is there something else I need to convert or calculate?
 
julz3216 said:
But this is wrong, is there something else I need to convert or calculate?

Without doing any other math I would note the diameter is .318m.

Always, always stay in SI units wherever possible.
 
Oh ok, that's what I did wrong. I got it. Thank you!
 
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