Solving for Force & Fly-Off Time on Rotating Mass in Cup

AI Thread Summary
The discussion focuses on solving a physics problem involving a stone of mass 100 kg on a rotating arm. The participants are attempting to calculate the stone's acceleration and the force acting on it when the arm is at an angle of pi/4 radians, while also determining when the stone will fly off the arm. One user initially miscalculated the acceleration, leading to confusion over the notation used for unit vectors e(r) and e(theta). After clarification, it was revealed that the error stemmed from not properly integrating the angular acceleration, specifically overlooking the cosine factor. The conversation highlights the importance of understanding the underlying equations and notation in solving rotational dynamics problems.
thoughtclaw
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1. The stone of mass m=100 kg is placed inside the cup at the end of a rotating arm of length l=3 m. If arm is released from rest at theta=0 and its angular acceleration is given as theta (double dot) = 5 rad/s2 cos t (a) find the acceleration of the stone with theta=pi/4 rad; (b) what is the force acting on the stone from the cup at this instant (include gravity); (c) at what time does the stone fly off the arm?



2. I'm thinking the equation to start with is a(p)=(r(double dot)-r*theta(dot)2)e(r) + (r*theta(double dot)+2r(dot)theta(dot))e(theta)



3. Using the above equation, with the assumption that r(dot) and r(double-dot) are zero, I found that the acceleration at pi/4 was -14.8e(r) + 2.34 e(theta). But the answer given is -21.71e(r) + 12.64e(theta). I cannot figure out what I did wrong. Can anyone help me?
 
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thoughtclaw said:
1. The stone of mass m=100 kg is placed inside the cup at the end of a rotating arm of length l=3 m. If arm is released from rest at theta=0 and its angular acceleration is given as theta (double dot) = 5 rad/s2 cos t (a) find the acceleration of the stone with theta=pi/4 rad; (b) what is the force acting on the stone from the cup at this instant (include gravity); (c) at what time does the stone fly off the arm?
2. I'm thinking the equation to start with is a(p)=(r(double dot)-r*theta(dot)2)e(r) + (r*theta(double dot)+2r(dot)theta(dot))e(theta)
3. Using the above equation, with the assumption that r(dot) and r(double-dot) are zero, I found that the acceleration at pi/4 was -14.8e(r) + 2.34 e(theta). But the answer given is -21.71e(r) + 12.64e(theta). I cannot figure out what I did wrong. Can anyone help me?
I am having difficulty following our notation. What does e(r) mean? or e(theta)? What is t? Is that the angle or time?

To do this problem, it is easier to first determine \dot{\theta}, \text{ and } \ddot{\theta} as functions t, whatever t is.

Then work out the acceleration using: a = \ddot{\theta}r

AM
 
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Thanks, Andrew. With your help, I've figured out that my problem was in the integration, forgetting to factor in the cosine of zero being 1.

The e(r) and e(theta) are the unit vectors, as my professor uses them in this class. I don't know how to do the fancy equation editor stuff that you just did, but perhaps I should learn. :)
 
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