Solving for I: A Puzzling Problem

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The discussion revolves around solving for current (I) in a physics problem, where initial calculations yielded an incorrect value of 0.0043A. Participants clarify that unit conversion from centimeters to meters is crucial, correcting the value to 0.0427A. The resistance used in calculations should only consider the length of the side relevant to the specific segment being analyzed, leading to a revised formula for resistance. There is a consensus that adjusting the resistance calculation is necessary for obtaining the correct current value. The conversation highlights the importance of accurate unit conversion and resistance consideration in solving such problems.
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Homework Statement



attached

Homework Equations





The Attempt at a Solution


I=BLv/R=.0043A which is obviously wrong, not sure why though?
 

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pat666 said:

Homework Statement



attached

Homework Equations





The Attempt at a Solution


I=BLv/R=.0043A which is obviously wrong, not sure why though?
parta=4.274A
partb=clockwise
partc=0A
partd=no direction
parte=4.273A
partf=anti-clockwise...
you didn't convert cm unit into meter...hope this was helpful...
 
if that's right than I must just have a wrong exponent somewhere
 
mind telling me how you got that because I checked mine and I keep getting 0.00427A??
 
yupe...you correct...its 0.0427...sorry for previous answer and inconvinience...so wats the problem now...you getting the answer...
 
No,thats not the answer, I tried that but it tells me its incorrect.
 
here the resistance 3.5ohm is of the whole loop.But,we have to consider resistance of only the length of the side which we are considering in calculation...
R=(3.5*8)/40.
now do calculation and hope you will get the answer... :)
 

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