Solving for Minimum Velocity: Ball & Rock

AI Thread Summary
The discussion centers on determining the minimum velocity required for a ball to avoid touching a rock during its fall. The solution involves analyzing forces, specifically the normal force acting on the ball, which is questioned in terms of its necessity when the ball is falling. It is clarified that the normal force becomes zero at the minimum speed needed to prevent contact with the rock. The participants emphasize that while gravity acts on the ball, centripetal acceleration is not a force in this context. The overall objective is to find the speed at which the normal force transitions from non-zero to zero, ensuring the ball remains airborne.
frostchaos123
Messages
16
Reaction score
0

Homework Statement



As in the attachement, find the minimum v such that the ball does not touch the rock.


The Attempt at a Solution



The solution given is mg*cos(theta) - mv^2/R = n < 0, where theta is the angle between the ball and the person.

My question is why is there a normal force acting on the ball? Since the ball is falling downwards without hitting the rock, wouldn't there be no forces acting on it other than centripetal acceleration?
 

Attachments

  • diagram.png
    diagram.png
    36.7 KB · Views: 460
Physics news on Phys.org
What is a "normal force" according to your definition?

This is simply a case of the rock moving along the x-axis (the kick) farther than it would by falling in the y axis.

I don't see centripetal anything entering into the problem.
 
frostchaos123 said:
My question is why is there a normal force acting on the ball?
Note that to find the minimum speed they set the normal force to zero.
Since the ball is falling downwards without hitting the rock, wouldn't there be no forces acting on it other than centripetal acceleration?
As long as the ball does not make contact with the rock, the only force on the ball is gravity. (Centripetal acceleration is not a force.)

The idea is this. First have the ball making contact with the rock as it slides down. There's a non-zero normal force, given by the equation you quoted. Find the speed which makes that normal force zero.
 
Doc Al said:
Note that to find the minimum speed they set the normal force to zero.

As long as the ball does not make contact with the rock, the only force on the ball is gravity. (Centripetal acceleration is not a force.)

The idea is this. First have the ball making contact with the rock as it slides down. There's a non-zero normal force, given by the equation you quoted. Find the speed which makes that normal force zero.

Is the ball moving?
 
AC130Nav said:
Is the ball moving?
Sure.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top