Solving for Spring Constant of Oscillating Spring

AI Thread Summary
To find the spring constant of a vertical spring with a 7.0 kg mass oscillating with a period of 2.6 seconds, the frequency is calculated as f = 1/T, resulting in approximately 0.385 Hz. The angular frequency w is determined using w = 2πf, yielding about 2.42 rad/s. The relationship w = √(k/m) is applied, leading to the equation 5.85 = k/7, which solves to k ≈ 40.96 N/m. While there may be minor rounding inaccuracies, the calculations are fundamentally correct. The approach using F = -kx was noted, but the absence of displacement 'x' made it unnecessary in this context.
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Homework Statement


A 7.0 kg mass is hung from the bottom end of a vertical spring fastened to the ceiling. The mass is set into veritcal oscillations with a period of 2.6s

Find the spring constant.

Homework Equations


w = \sqrt{k/m}
w = 2pi * f
f = 1/T

The Attempt at a Solution


f = 1/T
= 1/2.6
= 0.385 Hz
w = 2pi * 0.385
= 2.42
w = \sqrt{k/m}
w = k/7
5.85 = k/7
k = 40.96

Feel like my math could be wrong at the end there. Overall though, is this how its to be done? I tried using F = -kx...ma = -kx but I didn't have an 'x'.
 
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Yes that is how it should be done. Don't have a calculator to check your answers though.
 
There is some rounding inaccuracy but otherwise it is correct.

ehild
 
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