- #1

mouser

- 9

- 0

x(t) = -2/3cos10t + 1/2sin10t

Now, if I want to find the times when x(t) = 0... how would I go about that? In a similar problem that only involved a single term, I was able to use cos^-1 to solve for t, but in this case would that still hold? Setting x(t) to 0 I get:

0 = -2/3cos10t + 1/2sin10t

But now I'm stuck.

Any help would be greatly appreciated!