Solving for Vo in terms of Vs/Vx

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The discussion centers on solving for Vo in terms of Vs and Vx using voltage division and resistor combinations. Participants calculated Vx using the formula Vx = Vs(R1/(R1+R2)) and found Vo to be a function of Vx, with differing expressions presented. There was confusion regarding the units and values of the resistors, leading to clarifications about their parallel combination and the implications for current calculations. The conversation emphasized the importance of maintaining symbolic expressions for clarity, particularly when specific values for Vs are not available. Ultimately, the participants reached a consensus on the relationships between the variables involved.
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2. Vx= Vs(R1/R1+R2), V=IR
3. I combined the 1k Ω and 5k Ω resistors then used voltage division to find Vx. I used Vx to find Vo which I found to be (5/18)Vx. I don't know where I can do KCL or KVL to solve for Vx.
 
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eatsleep said:
attachment.php?attachmentid=58937&stc=1&d=1369225726.gif



2. Vx= Vs(R1/R1+R2), V=IR



3. I combined the 1k Ω and 5k Ω resistors then used voltage division to find Vx. I used Vx to find Vo which I found to be (5/18)Vx. I don't know where I can do KCL or KVL to solve for Vx.

You used voltage division to find Vx. What did you get?

Can you show your work for finding Vo in terms of Vx? The expression you gave doesn't look right to me.
 

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Doing voltage division I found Vx = (2/5)Vs. After combining the two resistors on the right side and doing ohm's law I found that Vo = (5/6)(1/.3)Vx = (mistake) is 5/1.8=2.8Vx.
 
Check your value for the combined resistors. Pay attention to the units used. Also take a look at your current expression; why do you divide by 0.3S? The current is specified to be 0.3S*Vx.
 
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gneill said:
Check your value for the combined resistors. Pay attention to the units used. Also take a look at your current expression; why do you divide by 0.3S? The current is specified to be 0.3S*Vx.

Does .3S not mean .3 Siemens = 1/Resistance ?
 
eatsleep said:
Does .3S not mean .3 Siemens = 1/Resistance ?

Yes. And Volts x Siemens = Current. That's a controlled current source.
 
gneill said:
Yes. And Volts x Siemens = Current. That's a controlled current source.

Ok, so then Vo=.25Vx?, I also have Vx=.4Vs
 
eatsleep said:
Ok, so then Vo=.25Vx?, I also have Vx=.4Vs

Again, what are the units for the two resistors in parallel? How many ohms does their parallel combination make? Your expression for Vx looks okay.
 
gneill said:
Again, what are the units for the two resistors in parallel? How many ohms does their parallel combination make? Your expression for Vx looks okay.

They are in kiloohms, their parallel combination makes (5*1)/(5+1) = 5/6 kΩ, 833Ω
 
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eatsleep said:
They are in kiloohms, their parallel combination makes (5*1)/(5+1) = 5/6 kΩ, 833Ω

Right. Or, if you want to retain accuracy, call it 5000/6 = 2500/3 Ohms. So multiplying your 0.3Vx by 2500/3 gives...
 
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Vo=250Ω*Vx, so now I have Vx = .4Vs and Vo = 250Vx. I could substituite Vx into Vo, but I do not have a value for Vs.
 
  • #12
eatsleep said:
Vo=250Ω*Vx, so now I have Vx = .4Vs and Vo = 250Vx. I could substituite Vx into Vo, but I do not have a value for Vs.

Nor do you need one... you are looking for Vo in terms of Vs, so a symbolic solution is fine.
 
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  • #13
gneill said:
Nor do you need one... you are looking for Vo in terms of Vs, so a symbolic solution is fine.

Oh well then, thanks for the help.
 

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