Solving for Water Temperature: 4000J Added to 400g at 20°C

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To determine the resulting temperature of 400 grams of water after adding 4000J of heat energy at an initial temperature of 20°C, the specific heat capacity formula is needed. The specific heat capacity equation relates energy, mass, and temperature change. Users are encouraged to refer to their textbooks or provided resources for the specific equation. Some participants express frustration over not finding the necessary information in their materials. Understanding the specific heat capacity is essential for solving this problem effectively.
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4000J of heat energy are added to 400 grams of water at 20 degrees celcius. What is the resulting temperature of the water?

I know that I'm supposed to find Kelvin (K) but I'm not sure on which equation to use..
 
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Look in your textbook and class notes, you should be able to find an equation that relates the quantities that are given / asked for (energy, mass, temperature).
 
Redbelly98 said:
Look in your textbook and class notes, you should be able to find an equation that relates the quantities that are given / asked for (energy, mass, temperature).


Thats why I asked because I really can't find it in the book or notes

Please just tell me the equation xD
 
It's at the link Tsportmat gave. Have a look.
 
I started physics 2 months ago so I haven't a clue of most of the stuff in that link, we have'nt come across it yet

Anyway nevermind :frown:
 

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