Solving for x in 3^(log(base4)x)

  • Thread starter Thread starter turutk
  • Start date Start date
  • Tags Tags
    Integrate
turutk
Messages
15
Reaction score
0

Homework Statement



integrate 3^(log(base4)x)

Homework Equations


The Attempt at a Solution



i tried to write it in different ways. couldn't solve.
i tried to divide the whole thing by ln3 and then add some more constants to cancel out the remainings. still i could not cancel out the x in the denominator which comes from the chain rule.
 
Physics news on Phys.org
First, change the base of the log to base 3, using the correct formula.
Then apply the formula 3^{\log_3(x)}=x.
 
thank you very much for your help. at least i succeed
 
So you have to integrate

3^{x\ln 4}

Then you'll have to integrate

\left(e^{\ln 3}\right)^{x\ln 4}

which should be trivial, right ?

Unless you may have to integrate

3^\log_4 x

in which case you have to integrate

\left(e^{\ln 3}\right)^{\frac{\ln x}{\ln 4}}

which again should be trivial.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top