Solving Frictional Forces Homework

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The discussion revolves around solving a homework problem related to frictional forces, where the gravitational force is approximately 750 N. The participant calculates the frictional forces acting on a wall, using the equation Ffriction < μ*N, leading to a result of about 910 N. They express confusion over the textbook's answer of 52 N, questioning how that could support the gravitational force. Others in the thread agree with the participant's calculations and seek clarification on the discrepancy with the book's answer. The conversation emphasizes the importance of understanding the relationship between weight, friction, and normal force in solving such problems.
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Homework Statement



In the attachment


Homework Equations



F = ma
F = mg
Ffriction < μ*N

3. Attempt at a Solution

Okay so I know that the weight is weighing down with a gravitational force of ~750 N. Similarly, I know that the two forces on the wall will both provide frictional forces pointing up with a magnitude equal to μ*F.

So I set (mg)/2 = μ*F and got something along the lines of 910 Newtons. I'm convinced this is correct because I can see no other way to do it. The book's answer is 52 Newtons which doesn't make sense because you'd have a combined force of 104 Newtons holding up a gravitational force of ~750 Newtons.

I'm looking for someone to either confirm that I'm doing it correct or point out what I'm doing wrong. Thanks.
 

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I get the same answer as you.

Chet
 
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