Solving Height Above Water Homework: 79kg Person Jumping 100m

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A 79kg person jumps from a 100m platform attached to a bungee cord with a spring constant of 40 N/m and a length of 35m. To find the height above water at maximum elongation, the gravitational potential energy at the jump height is converted into spring potential energy. At maximum elongation, the jumper's gravitational potential energy equals the spring potential energy, indicating that the jumper is no longer falling and is about to ascend. The solution requires applying the equations of motion and energy conservation principles. Understanding the relationship between potential energies is crucial for solving the problem.
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Homework Statement



79kg person jumps from a platform that is 100m above the water. He is attached by a bungee chord with sprint constant 40 N/m and length 35 m. Now he jumps off. How far is he above the water now when the chord has reached maximum elongation

Homework Equations




F=ma, Ek= 1/2mv2 Ep=mgh...etc

The Attempt at a Solution



I'm kind of stuck.. I know it involves energy, but the maximum elongation of the chord confuses me.
 
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All that it means is that the person is no longer falling and is just about to begin moving upward. In other words, the bunjee jumpers gravitational potential energy has been fully converted into the spring potential energy.
 

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