Solving IGBT Turn On Issue: Increase Vge from 10V to 15V

  • Thread starter Thread starter billy fok
  • Start date Start date
  • Tags Tags
    Igbt Turning
AI Thread Summary
To resolve the IGBT turn-on issue, increasing the gate-emitter voltage (Vge) from 10V to 15V is necessary. A suitable driver capable of supplying up to 20V and delivering the required 15V output is recommended. The discussion highlights that the current driver design may not adequately charge the capacitor between Vb and Vs, affecting performance when the IGBT is activated. Suggestions include using a ferrite transformer with a 5V square wave to create a stable 16V supply for the driver, rather than relying on voltage multiplier circuits. Overall, finding a compatible driver and ensuring proper voltage supply are crucial for successful IGBT operation.
billy fok
Messages
40
Reaction score
0
i have trouble to ON IGBT..
to turn on the IGBT, it needed the Driver to turn it on..
pwm pump in 5V into the driver signal. I supply 10v to power up the driver chip.
My design requirement to turn on the IGBT Vge is 15v... how to increase the Vge.

i have attached the circuit that i using.
 

Attachments

  • driver.png
    driver.png
    23.9 KB · Views: 546
Engineering news on Phys.org
Maybe you must find a matching driver ( google driver+IGBT ).

You can easily find a driver that is supplied by up to 20V, and can deliver the 15V output
 
Hesch said:
Maybe you must find a matching driver ( google driver+IGBT ).

You can easily find a driver that is supplied by up to 20V, and can deliver the 15V output
hi. my driver that i choose can supply to 20V? and my Vout is from 10v to 20v...
 
As I read your attached diagram, the capacitor between Vb and Vs will be charged through the diode to 5V, whenever the IGBT is turned off (assuming that the load is connected to Vs and ground ). When the IGBT is turned on, Vs will rise to ≈600V, and because the capacitor is charged, Vb will rise to 605V. In all circumstances you can control VHO in a range of 0 .. 5V with respect to Vs.

To extend this range, you must somehow increase the voltage Vb-Vs. There are voltage multiplier circuits, based on capacitor-diode networks, to be found, but I will not recommend that, as they are not rigid enough to this application. Not having a 16V supply available (15V+1), I would prefer a small ferrite transformer fed with some 5V sqarewave. Rectify the secondary voltage, and you have a stable 16V supply for the driver.

Sorry for my delayed answer, but I am from Denmark and is having a little fight with my dictionary.
 
Last edited:
While I was rolling out a shielded cable, a though came to my mind - what happens to the current flow in the cable if there came a short between the wire and the shield in both ends of the cable? For simplicity, lets assume a 1-wire copper wire wrapped in an aluminum shield. The wire and the shield has the same cross section area. There are insulating material between them, and in both ends there is a short between them. My first thought, the total resistance of the cable would be reduced...
Hey guys. I have a question related to electricity and alternating current. Say an alien fictional society developed electricity, and settled on a standard like 73V AC current at 46 Hz. How would appliances be designed, and what impact would the lower frequency and voltage have on transformers, wiring, TVs, computers, LEDs, motors, and heating, assuming the laws of physics and technology are the same as on Earth?
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
Back
Top