Solving Incomplete Integral: Easy Steps and Tips | Andishe9

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Hi all,
can anybody complete my answer?(I'm unable to solve the second part of the integral)
problem and answer(incomplete) : www.andishe9.com/integral.bmp[/URL]

thanks and excuse me for english;)
 
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Hamid1 said:
Hi all,
can anybody complete my answer?(I'm unable to solve the second part of the integral)
problem and answer(incomplete) : www.andishe9.com/integral.bmp[/URL]

thanks and excuse me for english;)[/QUOTE]

Hi Hamid1! Welcome to PF! :smile:

[SIZE="1"](have an integral: ∫ :wink:)

your link isn't working …

can you please type out your answer?
 
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Thank you,
I checked the link.It works...
 
ermmm...your very first line is incorrect: your basically claiming that (2x+6)-6=1 which is clearly false.

Try a u-substitution of the form u=x+3 instead.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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