Solving Integral: Different Answer with U-Substitution

[LocationX]

this integral can be solved without u-subsitution however, I get a different answer when I use u-sub.

\int \frac{6}{x-6} dx

u=x-6

du=dx

\int \frac{1}{6u}=\frac{1}{6}ln(x-6)

if U-sub wasnt used, then the answer would be 6ln(x-6)

what am I doing wrong in the subsitution?

 

[James R]

With the substitution, the integral is:

\int \frac{6}{u} du

not

\int \frac{1}{6u} du