Solving Kinematics: Police Car Chasing Speeders

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The discussion focuses on solving a kinematics problem involving a police car chasing a speeder. The key points include determining the time it takes for the police car to catch up to the speeder, the distance traveled during the chase, and the speed of the police car upon catching the speeder. Participants emphasize the need to track both vehicles' displacements and suggest using kinematic equations that relate displacement, initial velocity, acceleration, and time. The confusion arises from managing the two objects' movements simultaneously. Understanding these concepts is crucial for accurately solving the problem.
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Homework Statement


A police car stopped at a set of lights has a speeder pass it at 100 km/h. If the police car can accelerate at 3.6 m/s squared

a) how long does it take to catch the speeder

b) how far would the police car have to go before it catches the speeder?

c) what would its speed be when it caught up with the car? Is this speed reasonable?


Homework Equations



not sure about these but:

v2 = v1 + a(delta)t

d = speed over time.

The Attempt at a Solution



At first I thought I just needed to calculate how long it would take for the police car to get to 100 km/h, but then I realized that the speeder is going 100km/h. I'm just really confused because there are two objects that you have to keep track of instead of just one. I have no clue where to start on this question.
 
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Since you know that you are trying to find the time taken for the police car to catch the other car, you know that when he does, their displacements are going to be the same. So if you get an equation for the displacement of each car, you can equate them to each other to find the time. So do you know a kinematic equation that relates displacement, initial velocity, acceleration and time?
 
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