Solving Newton's Law Problem: Force on the Rope w/ 56N Sled

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SUMMARY

The problem involves calculating the force exerted on a rope by a child holding a 56N sled on a frictionless incline of 25 degrees. The correct approach requires recognizing that the sled's weight acts straight down, and the force along the incline must counteract the component of weight acting down the slope. The accurate calculation for the force exerted on the rope is 56*cos(25), resulting in approximately 50.50N, not the previously calculated 23.67N.

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Homework Statement



A child holds a sled on a frictionless, snow-covered hill, inclined at an angle of 25 degrees.If the sled weighs 56 N, find the force exerted on the rope by the child.

Homework Equations


[itex]\Sigma[/itex]F=ma


The Attempt at a Solution


I set up a right triangle with 56N as the hypotenuse. I then figured the x component of force, or the force exerted on the rope by the child, to be 56sin25. I got 23.67N but when I submitted this it was wrong am I missing something here.

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That answer looks right to me.
The method is not. The 56 N acts straight down, and 56*sin(25) is the component acting downward along the hill. An equal force upward along the hill is needed to cancel it.
 

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