Solving Oscillating Mass Displacement Problem: Max Velocity Calc

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To solve the oscillating mass displacement problem, the maximum velocity of a 0.3 kg mass on a spring with a stiffness of 200 N/m can be calculated using conservation of energy principles. The mass is displaced 10 mm from its equilibrium position, and the gravitational force acting on it must be considered alongside the spring force. The amplitude of the oscillation is determined by the total displacement from the equilibrium position, which includes both the static and dynamic components. It is crucial to focus on oscillations around the equilibrium position rather than the unstretched length of the spring. Proper application of these concepts will yield the maximum velocity during the vibration.
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i know this problem is posted on this forum somwhere else but i can't quite understand thanks in advance

Homework Statement



A mass of 0.3 kg is suspended from a spring of stiffness 200 N m–1. If
the mass is displaced by 10 mm from its equilibrium position and
released, for the resulting vibration, calculate:

the maximum velocity of the mass during the vibration

Homework Equations



F=kl



The Attempt at a Solution



so far i am thinking that i need to use hookes law as follows so i can get the amplitude
F=k(l+x)

F= mg = 0.3 kg x 9.81 = 2.94 N
k = 200 Nm-1
l = static spring reflection = 2.94/200 = 0.01
x = displacement due to external force = 10mm

so the amplitude would be l + x = 10.01mm?

do i need to take into account the extra extension when attempting the solution or is it just f/k =l
or do i need to use f/k = l + x to calculate the amplitude


any help would be appriciated

Thanks
 
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The oscillations are around the equilibrium position, not the unstretched length.
Remember you have gravity as well as the string acting on the mass.

I would use conservation of energy for this problem.
For instance, at the top of the motion, the energy stored in the spring has been changed into gravitational potential energy.
 
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