Solving Plate Capacitor Problem with Voltage U

AI Thread Summary
To solve the plate capacitor problem with an applied voltage U, the electric field between the plates can be determined using the formula E = U/d, where d is the distance between the plates. The presence of a conducting plate with charge Q between the capacitor plates influences the electric field, as it behaves like an infinite charged plane, contributing to different field values above and below it. The capacitance is calculated using the formula C = (ε * A) / d, where A is the surface area and ε is the permittivity of the medium. Additionally, capacitance is defined as the ratio of charge to potential. Understanding these relationships is crucial for accurately determining the electric field in this scenario.
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Hi All,

I've been doing a few problems with plate capactors and I have this new one which introduces a voltage U. I haven't seen an example with a voltage befopre so I'm not sure where to start it. I'm hoping someone could start me off.

The problem goes like this: Find the electric field between the plates when a voltage U is applied to the cap. The cap consists of 2 plates (surface area F, distance d apart). Between the plates is a conducting plate of charge Q.

Thanks...
 
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THe capacitance is found as (epsilon)(area)/(distance). Also capacitance is defined as the ratio of (charge)/(potential). Lastly the relationship with the electric field is E=(potential)/(distance).

I think (someone check me on this) The charged conductor in between the plates will add to the electric field of the capacitor,(in the manner of an infinite charged plane) so there will be a different value for the field above and below this conductor, since it will add on one side and subtract on the other.
 
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