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HPRF
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Homework Statement
It is found that Poyntings vector gives
P = ExH = (mu0q2a2sin2(theta)/6pi2cr2)r
This apparently leads to
Total Power = (mu0q2a2/6pi2c)[tex]\int[/tex](sin2(theta)/r2)(2pir2sin(theta)d[tex]\theta[/tex])
What I am unsure of is where the
(2pir2sin(theta)d[tex]\theta[/tex])
appears from. Can anyone help?