Solving Projectile Motion: Finding Initial Velocity and Distance

AI Thread Summary
To find the initial horizontal velocity of a ball rolling off a 1.5 m high cliff and landing 3 m away, the time of flight must first be calculated using the equation for vertical motion. The vertical motion equation indicates that the time to fall can be derived from the height and acceleration due to gravity. Once the time is determined, the horizontal velocity can be calculated using the formula u_horizontal * t = 3. The discussion highlights the importance of combining equations to solve for unknowns in projectile motion problems. The solution was confirmed to be effective by the participants.
physics_challenged
Messages
4
Reaction score
0
Hi, can someone please tell me how to figure out the initial (horizontal) velocity of a ball that rolls horizontally off a cliff at a height of 1.5 m from the ground, and lands 3 m away from the edge of the cliff?
 
Last edited:
Physics news on Phys.org
u_horizontal *t = 3
1.5 = 0*t+(1/2)*g*t^2

-- AI
 
How long does the ball take to reach the ground? How fast does it have to travel horizontally to be 3 m out in that time?
 
Tide said:
How long does the ball take to reach the ground? How fast does it have to travel horizontally to be 3 m out in that time?


The problem is...the question doesn't give the time or speed. :cry:
 
You can always combine equations.
 
TenaliRaman said:
u_horizontal *t = 3
1.5 = 0*t+(1/2)*g*t^2

-- AI

Yes, that worked. Thanks a bunch! :smile:
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top