Solving Shear Strain Problem: Find Vertical Displacement

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The discussion focuses on calculating the vertical displacement of plate A under a vertical force of 5 N, considering shear strains in rubber pads with specified dimensions. The user seeks clarification on the use of a 40 mm horizontal length in their calculations and the origin of the equation used to derive the displacement. It is noted that the small angle approximation can simplify the calculations, allowing for the use of tangent approximations. The importance of understanding the relationship between shear strain and displacement in this context is emphasized. Overall, the thread highlights the need for clarity in applying formulas related to shear strain and displacement in engineering problems.
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Homework Statement


The support consists of three rigid plates, which
are connected together using two symmetrically placed
rubber pads. If a vertical force of 5 N is applied to plate
A, determine the approximate vertical displacement of
this plate due to shear strains in the rubber. Each pad
has cross-sectional dimensions of 30 mm and 20 mm.
Gr = 0.20 MPa.

Homework Equations



The Attempt at a Solution


http://www.academia.edu/6204124/Chapter_03
It is problem #3-33. I need help understanding the last part,
d =40(0.02083) =0.833 mm
Why do they use 40mm, the horizontal length of the padding. Also, where is this equation coming from?
 
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The last line is just trigonometry. Note that 0.02083 Rad is a very small angle so you can make a suitable approximation for Tan rather than use Tan itself.
 
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