Solving Simple Trig Identities Homework Problem

  • Thread starter Thread starter Sneaky07
  • Start date Start date
  • Tags Tags
    Identity Trig
AI Thread Summary
The discussion focuses on simplifying the expression f(t) = sin(βt) * cos(βt). The initial approach involved using the sine addition formula but led to no progress. A breakthrough occurred when recognizing the identity 2sin(x)cos(x) = sin(2x), allowing for the transformation of the expression. Ultimately, the solution was derived as f(t) = (1/2)sin(2βt). This demonstrates the effective application of trigonometric identities in simplifying expressions.
Sneaky07
Messages
6
Reaction score
0

Homework Statement



Simplify this expression:
f(t) = sin(\betat)*cos(\betat)

Homework Equations



Identities

The Attempt at a Solution



I started out by doing sin(\betat)*sin(\betat+\pi/2) but I can't go anywhere from there. If I use the sin(a+b) formula it brings me back to the original formula which it should. Anyone have an idea? Just the start would be MUCH appreciated.
 
Last edited:
Physics news on Phys.org
You have f(x) but no x anywhere on the other side. What is the variable and what is constant?
 
Sorry about that. It should be f(t).
 
The first thing that came to mind was 2sinxcosx = sin2x
 
Ahh! I think that is what I needed. If 2sin(x)cos(x)=sin(2x) then I can multiply both sides by 2 which gives 2f(t)=2sin(\betat)cos(\betat). After, just carry the 2 over so you get f(t)=(1/2)sin(2\betat). Thanks man!
 
Back
Top