Solving Sound Intensity with 2 Shut-Off Engines

AI Thread Summary
The discussion centers on calculating sound intensity when two out of three equally noisy engines, each producing 120 dB, are shut off. The initial calculation shows that the intensity for three engines is 1 W/m2. However, confusion arises regarding the intensity when two engines are turned off, as the user mistakenly believes the intensity should be divided by three. Clarification is needed on how decibels work, particularly that sound intensity does not scale linearly with the number of sources. Understanding the logarithmic nature of decibels is crucial for solving the problem accurately.
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Homework Statement


A person is a certain distance away from a plane with three equally noisy engines at 120 dB. What is the sound intensity if two of the engines are shut off?


Homework Equations


B (in dB) = log I/Io


The Attempt at a Solution


using this equation:
120 dB = 10 log I/Io
10^12 = 10 log (I/10^-12 W/m2)
I = (10^12)(10^-12)
I = 1 W/m2

So, intensity for three engines is 1 W/m2. If two engines turned off, then I'm pretty sure you don't divide the answer by three to get 0.33 W/m2 per engine because the answer is 116. I can't figure out what I'm doing wrong.
 
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On the second line in your solution, where did 1012 come from?
 
Sorry, this should read:

120 dB = 10 log (I/10^-12 W/m2)
10^12 = I \(10^-12)
I = (10^12)(10^-12)
I = 1 W/m2
 
any ideas?
 
I think you need to better understand the meaning of decibel. This might help: http://hyperphysics.phy-astr.gsu.edu/hbase/sound/db.html"
 
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