Solving Superposition Theorem for I(R1)

AI Thread Summary
The discussion revolves around solving for the current I(R1) in a circuit using the superposition theorem. The poster initially calculates I'(R1) as 3.3mA with the voltage source active and the current source open, and I''(R1) as 3mA with the current source active and the voltage source shorted, leading to a total of 6.3mA. However, a respondent points out that the poster neglected a 20-ohm resistor, which affects the calculations. They suggest recalculating the current through R1 by considering each source individually without combining them incorrectly. The final answer indicated in the original problem is only 3.3mA, suggesting a need for reevaluation of the calculations.
frostchaos123
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Homework Statement



Hi all

I have been struggling to find the right ans for the I(R1) in this circuit.

First i consider only the voltage source by opening the current source. As such i find that I'(R1) = (4-0.7)/1K = 3.3mA

Secondly i consider the current source by shorting the voltage source. Thus i derive I''(R1) = 3mA

Finally i get I(R1) = I'(R1) + I''(R1) = 3.3m + 3m = 6.3mA

However the ans seems to indicate as only 3.3mA.

Please help to see if my reasoning is correct.

Thanks.
[PLAIN]http://img823.imageshack.us/img823/8508/circuit.png
 
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You've neglected the 20-ohm resistor completely. Try recalculating everything taking it into account.
 
When you shorted the voltage source, I think you assumed you could combine the two voltage sources together like you did in the first part of the calculation, but you cant. Try calculating the current through R1 just one source at a time - the current source, V1, then V2.
 

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