I Solving the Brachistochrone problem with friction

physics_cosmos
Messages
6
Reaction score
0
This Wolfram Alpha Page contains a derivation of the parametric form of the brachistochrone curve that result from either assuming friction or its absence.

I am asking for help understanding how the solution to the differential equation obtained from applying the Euler-Lagrange equation to the integrand of the the integral representing the total time of descent is obtained. This differential equation can be found on step (30) of the page. I am asking for help in understanding the next step, how setting dy / dx = cot(theta/2) results in the given parametric forms for x and y (in terms of theta), as given in steps (32) and (33).
 
Physics news on Phys.org
Is that step simply choosing an integrating factor that fits the differential equation you're trying to solve?
 
jedishrfu said:
Is that step simply choosing an integrating factor that fits the differential equation you're trying to solve?

I don't believe the differential equation is linear, or resolvable into linear form, so I don't think that that would help me get to a solution. I hope you can help me find another way, though.
 
Last edited:
There is the following linear Volterra equation of the second kind $$ y(x)+\int_{0}^{x} K(x-s) y(s)\,{\rm d}s = 1 $$ with kernel $$ K(x-s) = 1 - 4 \sum_{n=1}^{\infty} \dfrac{1}{\lambda_n^2} e^{-\beta \lambda_n^2 (x-s)} $$ where $y(0)=1$, $\beta>0$ and $\lambda_n$ is the $n$-th positive root of the equation $J_0(x)=0$ (here $n$ is a natural number that numbers these positive roots in the order of increasing their values), $J_0(x)$ is the Bessel function of the first kind of zero order. I...
Back
Top