Solving the Homogeneous Equation y2dx -x(2x+3y)dy =0

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SUMMARY

The discussion focuses on solving the homogeneous differential equation represented by y²dx - x(2x + 3y)dy = 0. The user successfully transformed the equation into a homogeneous form and attempted a substitution with x = uy, leading to the equation y²udy + y³du - 2x²dy + 3yxdy = 0. The conversation highlights the equivalence of the substitution methods x = uy and y = ux, and suggests dividing the resulting equation by x² for simplification.

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mamma_mia66
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Homework Statement


y2dx -x(2x+3y)dy =0 I have to recognize the equation and solve it


Homework Equations





The Attempt at a Solution



I did y2dx - (2x2+ 3yx) dy=0
which is a homogeneous now
after I substitude x=uy
dx=udy + ydu

I stuck here after the substitution

y2udy+y3du - 2x2dy + 3yxdy=0

please someone help if I am not in right direction from the begining.
 
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mamma_mia66 said:

Homework Statement


y2dx -x(2x+3y)dy =0 I have to recognize the equation and solve it


Homework Equations





The Attempt at a Solution



I did y2dx - (2x2+ 3yx) dy=0
which is a homogeneous now
after I substitude x=uy
dx=udy + ydu

I stuck here after the substitution

y2udy+y3du - 2x2dy + 3yxdy=0

please someone help if I am not in right direction from the begining.
I am more accustomed to write y= ux but your method is equivalent.
Saying x= uy is the same as saying u= y/x. Divide your last equation by x^2 and see what you get!
 
ok, thanks.
 

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