use the information to solve the triangle: b=1, c=the square root of (3)+1, B=15 degrees.
given that sin15 degrees =the square root of 6 -the square root of 2 divided by 4. FYI.. is in the square root and than add one.
The formulas given the law of sin sinA/a=sinB/b=sinC/c
The law cosine
The Attempt at a Solution
I used the law of sin to find angle C. The problem is written out as the square root of (3)+1 Sin(15)/1. I came out with .70 degrees for angle c. For some reason I can't get that answer again. Also I'm not sure which formula I should be using.