Solving Trig Equations In A Given Range

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Homework Statement



Solve cos(3θ) = 0.85 in the range 0 ≤ θ ≤ 360°

Homework Equations





The Attempt at a Solution



cos(3θ) = 0.85

3θ = 31.79°

θ = 10.6° (3 s.f)

I have drawn my transformed cos curve, where the full wave completes after 120°, so there are 3 full cycles in my range.

I often make silly mistakes and I'm not sure of the best method to check my results.

Using the symmetry of the curve I have calculated that θ = 10.6°, 109.4°, 130.6°, 229.4°, 250.6°, 349.4°.

So, how do I verify these?
 
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For what quadrants is the cosine positive?
 
1 and 4
 
Which of your solutions meet this criteria?
 
Hi BOAS! :smile:
BOAS said:
cos(3θ) = 0.85

3θ = 31.79°

Easier if you write:

cos(3θ) = 0.85

3θ = 2nπ ± 31.79° :wink:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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