Solving trig equations using Addition formula

AI Thread Summary
To solve the equation sin(x+∏/6)=2cosx for 0≤x≤2∏, the first step involves using the addition formula for sine, resulting in the equation 2cosx=(√3)/2sinx+1/2cosx. From there, it is suggested to subtract (1/2)cos(x) from both sides to simplify the equation. The next step is to express the equation in terms of tangent for easier solving. Utilizing the identity a sin x + b cos x = √(a²+b²) sin(x+ϕ) may also aid in the solution process.
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Homework Statement



Solve the equation: sin(x+∏/6)=2cosx for 0≤x≤2∏

Homework Equations



sinAcosB+cosAsinB

The Attempt at a Solution



sin(x+∏/6)=2cosx

2cosx=(√3)/2sinx+1/2cosx

How do I solve from here?
 
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Moved the thread to precalc. Please post in the correct forum next time.
 
Hi studentxlol! :smile:

Perhaps you can use the following trig identity?

a sin x + b cos x = √(a2+b2) sin(x+ϕ)

where cos ϕ = a/√(a2+b2)
and sin ϕ= b/√(a2+b2)
 
studentxlol said:

Homework Statement



Solve the equation: sin(x+∏/6)=2cosx for 0≤x≤2∏

Homework Equations



sinAcosB+cosAsinB

The Attempt at a Solution



sin(x+∏/6)=2cosx

2cosx=(√3)/2sinx+1/2cosx

How do I solve from here?

The first, obvious, step is to subtract (1/2) cos(x) from both sides. Then get a tangent.
 
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