Solving Trigonometric Equations Using Identities

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The discussion focuses on solving trigonometric equations using identities, specifically addressing two equations involving tangent and sine functions. Participants explore transformations of the equations into sine and cosine forms, simplifying them to reach equivalent expressions. The conversation highlights the challenge of performing mathematical operations on a computer versus using traditional pen and paper methods. There is a shared sentiment about the difficulty of typing out equations and a preference for manual calculations. Overall, the thread emphasizes the importance of understanding trigonometric identities and the simplification process in solving these equations.
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1)
tan(x)-sin(x)/2tan(x) = sin^2(x/2)
1-sin(x)/2 = sin^2(x/2)

(That's as far as I've gotten on this one...but i don't know if I'm in the right direction or what to do next?)

2)
sin2x = 1 / tanx + cot2x
2sin(x)cos(x) = ''
sin(x) * cos(x) * sin(x) = ''

(The same from #1 applies to this problem)
 
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Assuming you mean:
\frac{\tan(x)-\sin(x)}{2 \tan(x)} = \sin^{2}(\frac{x}{2})

Let's change everything to cosinus and sinus

\frac{\frac{\sin(x)}{\cos(x)} - \sin(x)}{\frac{2 \sin(x)} {\cos(x)}} = \sin^{2}(\frac{x}{2})

Simplifying:

\frac{\frac{\sin(x) - \sin(x) \cos(x)}{\cos(x)}}{\frac{2 \sin(x)} {\cos(x)}} = \sin^{2}(\frac{x}{2})

\frac{\sin(x) - \sin(x) \cos(x)}{2 \sin(x)} = \sin^{2}(\frac{x}{2})

\frac{1 - \cos(x)}{2} = \sin^{2}(\frac{x}{2})

Remember \sin^{2}(\frac{x}{2}) = \frac{1 - \cos(x)}{2}

\frac{1 - \cos(x)}{2} = \sin^{2}(\frac{x}{2})

\sin^{2}(\frac{x}{2}) = \sin^{2}(\frac{x}{2})

Assuming you mean:
\sin (2x) = \frac{1}{\tan(x) + \cot(2x)}

Working the right to the left

Changing to sinus and cosinus:

\sin (2x) = \frac{1}{\frac{\sin(x)}{\cos(x)} + \frac{\cos(2x)}{\sin(2x)}}

Applying double angle identities

\sin (2x) = \frac{1}{\frac{\sin(x)}{\cos(x)} + \frac{\cos^2(x) - \sin^2(x)}{2 \sin(x) \cos(x)}}

Simplifying:

\sin (2x) = \frac{1}{\frac{2 \sin^2(x) \cos(x) + \cos^3(x) - \sin^2(x) \cos(x)}{2 \sin(x) \cos^2(x)}}

\sin (2x) = \frac{1}{\frac{\sin^2(x) \cos(x) + \cos^3(x)}{2 \sin(x) \cos^2(x)}}

\sin (2x) = \frac{1}{\frac{\sin^2(x) + \cos^2(x)}{2 \sin(x) \cos(x)}}

Remember \sin^2(x) + \cos^2(x) = 1

\sin (2x) = \frac{1}{\frac{1}{2 \sin(x) \cos(x)}}

Remember \sin(2x) = 2 \sin(x) \cos(x)

\sin (2x) = 2 \sin(x) \cos(x)

\sin (2x) = \sin (2x)
 
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damn it... how do u do all these equations on the computer?? i find it hard doing my math on a computer... I am more comfortable with a pen and paper... get tired of using the "^",etc

any words of wisdom ?
 
Jeez...that was incredible. Thanks a lot...but I don't suppose there was an easier way, was there? haha
 
jai6638 said:
damn it... how do u do all these equations on the computer?? i find it hard doing my math on a computer... I am more comfortable with a pen and paper... get tired of using the "^",etc

any words of wisdom ?

You get used to imagining it in your head.
 
lol i imagine it in my head too when possible but i just can't get myself to type it all down...Good ol' pen and paper!
 
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