Solving trigonometric equations

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To solve the equation cos(x) = -cos(2x), one can utilize trigonometric identities to express cos(2x) in terms of cos(x). This transformation leads to a quadratic equation in cos(x), which can be solved for values such as cos(x) = -1 and cos(x) = 1/2. The solutions for these values yield x = -π, x = π/3, and x = -π/3, with the general solution including integer multiples of 2π. Graphing may not provide clear solutions, but using tools like Wolfram Alpha can assist in finding answers. Understanding the relationship between angles on the unit circle is also crucial in solving such equations.
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Homework Statement


How do you solve cosx=-cos2x?


The Attempt at a Solution


I've tried graphing it, but just wasn't able to crack the solutions

Thanks for help!
 
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What is the relation between two angles a and b if cos(a)=-cos(b)? Look at the unit circle.

Or use the formula cos(2x)=cos^(x)-sin^2(x)

hild
 
If you merely want the answer (without proof), type "solve cos(x)=-cos(2x) for x" in wolfram alpha. If you want to figure out the proof, look up the trig formula that let's you express cos(2x) in terms of cos(x). With that substitution, you will have transformed your equation into a quadratic equation, with cos(x) as the unknown, the solution of which is cos(x)=-1 (implying x=-pi) or cos(x)=1/2 (implying x=pi/3 or x=-pi/3). Of course, add any integer multiple of 2pi to these answers to characterize the infinite number of solutions.
 
or use cos(2x) = 2cos2(x) - 1
 
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