Solving Vector Area dS of Sphere: Find Mistake!

aaaa202
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Homework Statement


I wonna calculate the vector area dS of a sphere, but for some reason my result gets mixed areound. I need a trained eye to see where I make a silly mistake.


Homework Equations


Parametrization of a sphere:

(x,y,z) = r(cos\phisin\theta,sin\phicos\theta,cosθ)

The Attempt at a Solution


So ∂r/∂\phi = r(cosθcos\phi,-sinθsin\phi,sinθ)
and
∂r/∂θ = r(-sin\phisinθ,cos\phisinθ,0)

and dS = ∂r/∂\phi x ∂r/∂θ = r2 (sinθcosθcos\phi,sin\phisinθ2, ...) dθd\phi

But the first two terms should be switched around according to my notes! Where do I go wrong? :(
 
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aaaa202 said:

Homework Statement


I wonna calculate the vector area dS of a sphere, but for some reason my result gets mixed areound. I need a trained eye to see where I make a silly mistake.


Homework Equations


Parametrization of a sphere:

(x,y,z) = r(cos\phisin\theta,sin\phicos\theta,cosθ)

The Attempt at a Solution


So ∂r/∂\phi = r(cosθcos\phi,-sinθsin\phi,sinθ)
and
∂r/∂θ = r(-sin\phisinθ,cos\phisinθ,0)

and dS = ∂r/∂\phi x ∂r/∂θ = r2 (sinθcosθcos\phi,sin\phisinθ2, ...) dθd\phi

But the first two terms should be switched around according to my notes! Where do I go wrong? :(

Well, you have the ##\theta## and ##\phi## reversed from the usual math notation for spherical coordinates, but I guess some physicists do that. But when you differentiated with respect to ##\phi## it looks like you differentiated the ##\theta## variables, and conversely.
 
nvm.. Found my mistake - the parametric equation was wrong.
 
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