Solving Vector Problems with Law of Sines and Pythagorean Theorem

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The discussion revolves around solving a vector problem involving a person walking 10m north and then 18m at an angle east of south. The user breaks down the movement into two vectors, calculating the components of the second vector using the Law of Sines and creating a triangle. They find the x and y components of the second vector to be 9 and 15.59, respectively, leading to total x and y components of 9 and 23.59. The user then calculates the angle using inverse tangent and the magnitude of the resultant vector with the Pythagorean theorem, arriving at a magnitude of 25.25. The user expresses uncertainty about their method and seeks confirmation on their calculations.
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Homework Statement


So a person walks 10m north, and then walks 18m at a degree of east of south. What is the magnitude and velocity? (Length and angle measure)


Homework Equations


Law of sines
Pythagorean theorem


The Attempt at a Solution


So I split up this problem into two vectors. The first vector is the guy walking north. So his y=8. His x=0 because he doesn't go anywhere in the x direction. Next I created a triangle to figure out the second vector. We know that the angle at the top of the triangle is 30 degrees. The hypotenuse is 18, and at the left bottom side of the triangle is a right angle (connecting the end of the hypotenuse to the y axis. After doing the law of sines the x2 (x of second vector) is 9. y2=15.59. Now I added the x's to get x total (xt) and the y total (yt). xt=9, yt=23.59. Then with these numbers i created a new triangle and did the inverse tan of 23.59 over 9 to get an angle measure of 69.1. Then pythagorean theorem will get me the hypotenuse of this triangle which is 25.25 and the magnitude of the vector. Am i doing this right? I just have a feeling I am not. Thank you for all your help :)
 
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