Solving Volume of Solid S w/ Squares Perpendicular to y-Axis

[kplooksafterme]

Homework Statement

Consider the solid S described below.
The base of S is the region enclosed by the parabola y = 5 - 2x2 and the x-axis. Cross-sections perpendicular to the y-axis are squares.
Find the volume V of this solid.

Homework Equations

The Attempt at a Solution

I know how to answer these types of questions, but my question is what exactly does the question ask for? I can find the area bound by the parabola and the x-axis, but what does "cross-sections perpendicular to the y-axis are squares" mean?
thanks for any help

 

[NateTG]

If the bounding functions were, for example, y=x+1, y=-x+1 and y=0[/itex] then the solid would be a square pyramid.<br /> <br /> The object that&#039;s being described is something like a sqare &#039;bubble pyramid&#039;.

 

[HallsofIvy]

Imagine squares made of foam. at the base of the parabola, since y= 5- 2x² has x-intercepts at \pm\sqrt{5/2} your square have height as well as base of length 2\sqrt{5/2} (and so area 10). As y increases the corresponding x values decrease and so does the height of the square. Your solid is bounded by 4 curved sides. Of course, there is the base which is that parabola itself. There will also be two "edges" arcing from (-1, 0, -\sqrt{5/2}) down to (0, 5, 0) and from (1, 0, \sqrt{5/2}) down to (0, 5, 0).