Solving with mathematical induction

gr3g1
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I have to solve:

1/2n <= (2n - 1)!/(2n!)

I have no idea how to approach this problem..

Any hints?
Thanks
 
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prove that it is true when n = 1. then you should show that 1/2(n+1) <= [2(n+1)! - 1)]/[2(n+1)!]
 
Where would I go from here?
 
What IS "proof by Induction"? Surely you didn't just walk into the wrong class!
 
I think I have to prove the RHS of the equation
is equivalent for P(k) and P(k+1)
is that right?
 
More precisely:

(2k - 1)! / (2k)! == (2(k+1)-1)! / (2(k+1)!)
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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