Solving with mathematical induction

gr3g1
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I have to solve:

1/2n <= (2n - 1)!/(2n!)

I have no idea how to approach this problem..

Any hints?
Thanks
 
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prove that it is true when n = 1. then you should show that 1/2(n+1) <= [2(n+1)! - 1)]/[2(n+1)!]
 
Where would I go from here?
 
What IS "proof by Induction"? Surely you didn't just walk into the wrong class!
 
I think I have to prove the RHS of the equation
is equivalent for P(k) and P(k+1)
is that right?
 
More precisely:

(2k - 1)! / (2k)! == (2(k+1)-1)! / (2(k+1)!)
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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