Solving Word Problem: Elevator Acceleration of 145 lb to 122 lb

  • Thread starter Thread starter BlueOwl
  • Start date Start date
AI Thread Summary
A person weighing 145 lb experiences an apparent weight of 122 lb in an elevator, indicating the elevator is accelerating downwards. The change in apparent weight is due to the elevator's acceleration, which can be calculated using the difference in weight. By converting the weights to Newtons and applying Newton's second law (F=ma), the net force can be determined. The mass is derived from the initial weight, allowing for the calculation of acceleration. Understanding the relationship between weight, tension, and acceleration is crucial for solving this problem.
BlueOwl
Messages
8
Reaction score
0

Homework Statement



A person that has a weight, on land, of 145 lb gets on an elevator to records an apparent weight of 122 lbs. What is the direction and magnitude of the elevator's acceleration?


Homework Equations



F=ma or F=mW


The Attempt at a Solution



I have no Clue how to do this any help will do :)
 
Physics news on Phys.org
BlueOwl said:

Homework Statement



A person that has a weight, on land, of 145 lb gets on an elevator to records an apparent weight of 122 lbs. What is the direction and magnitude of the elevator's acceleration?


Homework Equations



F=ma or F=mW


The Attempt at a Solution



I have no Clue how to do this any help will do :)

First, is the elevator accelerating upwards or downwards? How can you tell?

What causes the change in apparent weight?
 
Weight is a force, not an acceleration. Your weight is equal to F = ma = mg when standing on the Earth where g = -9.8m/s^2. When you're in an elevator, assuming you're being weighed, the acceleration of the elevator will either help cancel out or increase your weight which is something you can tell by our everyday experience. Since your mass doesn't change, you can determine the change in the acceleration you feel by comparing your weight on land and with the elevator in use. This change is equal to the elevator's acceleration.
 
Im still Confused . I know that the the elevator is accelerating downwards, reducing his apparent weight but how do I solve for the Magnitude?
 
Well you know the change in weight. With this, you can determine the acceleration since you can determine the mass from the initial part of the problem saying that someone weighs 145lb on Earth outside of the elevator.
 
If he is accelerating downwards then there has to be a net force going down also. I changed to Newtons so 642.25-542.9=ma. m=65.53. You can solve for a. It is easier to visualize him being on a string. That is another way to measure weight. So that makes mg-T=ma. T is the weight shown then.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top