- #1
kchau
- 5
- 0
Homework Statement
http://img152.imageshack.us/img152/4671/img3328cj5.jpg
Homework Equations
The Attempt at a Solution
i Found part a is 2.7
and b i think is 12.0N?
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Your logic is flawed. Draw a FBD of the top block and calculate its acceleration. The max friction force that can act on the top block without slippage is 12N. The 12N friction force is the only force acting on the top block. Once you get the acceleration, solve for F with a FBD of the system.kchau said:well I am not sure how to solve it, i just used logic.
basically the way i see it, there is always 4.4kg resting on top of the slab, and no matter where you push, there will always be 12.0N applied to both blocks at the same time, mainly becuase the bottom of the slab is frictionless.
Friction is a force that resists the relative motion between two surfaces in contact.
Friction is important because it allows objects to stay in place, prevents slipping and sliding, and enables us to walk and grip objects with our hands.
Friction can be calculated using the formula F = μN, where F is the frictional force, μ is the coefficient of friction, and N is the normal force.
The factors that affect friction include the roughness of the surfaces in contact, the force pressing the surfaces together, and the type of material the surfaces are made of.
Friction can be reduced by using lubricants or by smoothing or polishing the surfaces in contact. It can be increased by increasing the force pressing the surfaces together or by using materials with a higher coefficient of friction.