Guaicai
- 8
- 0
How the symmetric and antisymmetric have results: A=0,G=H and B=0,G=-H in last picture ?[emoji53]
Take a pencil and a paper then try drawing the symmetric one first where you have to substitute A=0, G=H into ##\psi_1##, ##\psi_2##, and ##\psi_3##. How does the resulting curve looks like if you make the ##x=0## line as a symmetrical line? Do the same for antisymmetric solution.Guaicai said:How the symmetric and antisymmetric have results: A=0,G=H and B=0,G=-H in last picture ?![]()