A recording engineer works in a soundproofed room that is 36.2 dB quieter than the outside. If the sound intensity in the room is 2.45 x 10-10 W/m2, what is the intensity outside?(adsbygoogle = window.adsbygoogle || []).push({});

It seems so ez yet I'm getting the wrong answer

ok so here is what I am able to do

the difference of 36.2dB is

I set 36.2dB to 10 log I/I0

and divide through by 10 on both sides so I get

log 10 ^ 3.52 = log I/I0

I get that I0 = 1x 10^-12 so

10^-12 x 10 ^3.62 would give me a I = 10 x -8.38 Is this the intensity difference? so when I add this value to my given value of inside the room I should get the value outside the room? But when I did this I got eh wrong answer.

Thanks for all ur help

Jason

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Sound Intensity and sound proofing

**Physics Forums | Science Articles, Homework Help, Discussion**