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It seems so ez yet I'm getting the wrong answer

ok so here is what I am able to do

the difference of 36.2dB is

I set 36.2dB to 10 log I/I0

and divide through by 10 on both sides so I get

log 10 ^ 3.52 = log I/I0

I get that I0 = 1x 10^-12 so

10^-12 x 10 ^3.62 would give me a I = 10 x -8.38 Is this the intensity difference? so when I add this value to my given value of inside the room I should get the value outside the room? But when I did this I got eh wrong answer.

Thanks for all ur help

Jason