Sound wave intensity of elephants

AI Thread Summary
Elephants communicate using infrasound, generating vocalizations as low as 14 Hz that can travel up to 10 km. The intensity of these sounds can reach 103 dB at a distance of 5 meters, corresponding to an intensity of 0.0199 W/m². To find the intensity level at 10 km, the relationship between intensity and distance must be applied, using the formula I1/R1² = I2/R2². After calculating the new intensity, it can be converted into decibels using the equation B = 10 log(I/10^-12). This approach will yield the intensity level of the infrasound at the specified distance.
sun
Messages
39
Reaction score
0

Homework Statement



There is evidence that elephants communicate via infrasound, generating rumbling vocalizations as low as 14hz that can travel up to 10km. The intensity level of these sounds can reach 103dB, measured a distance of 5.0m from the source. Deteremine the intensity level of the infrasound 10km from the source, assuming the sound energy radiates uniformly in all directions.


Homework Equations



B=10log(I/10^-12)

The Attempt at a Solution



i found the intensity at an intensity level of 103dB to be.0199W/m^2. I'm just not sure where to go from here. Suggestions would be appreciated.

thanks
 
Physics news on Phys.org
Intensityi is inversly proportional to square of the distance.
Using I1/R1^2 = I2/R2^2, find I2. Then convert it into dB.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top