Spaceship taking circular turn

AI Thread Summary
To solve the problem of a spaceship negotiating a circular turn, first convert the radius and speed into meters and seconds. The magnitude of angular velocity can be calculated using the formula ω = v/r, where v is the speed and r is the radius. Radial acceleration can be determined using the formula a_r = v²/r, while tangential acceleration is zero since the speed remains constant. Basic equations of curvilinear motion are essential for these calculations. Understanding these principles will enable accurate computation of the required values.
adp5025
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I tried using equations useing different methods of solving this problem but no cigar.

If anyone can help me just to get started that would be grand.

Thanks

A spaceship negotiates a circular turn of radius 3890 km at a speed of 33860 km/h.

(a) What is the magnitude of the angular velocity?
rad/s
(b) What is the magnitude of the radial acceleration?
m/s2
(c) What is the magnitude of the tangential acceleration?
m/s2
 
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First, convert given info to correct units; meters and seconds.
Second, use your equations for curviliear motion, they are quite basic.
Third, the answer to c should be obvious, since the problem states that the speed is not changing...
 
what equation would that be, i don't know one that's called curviliear motion equation.

i know these equations:
angular position
angular velcoity - i would guess to use this but there's not rad given.
angular acceleration
 
adp5025 said:
angular velcoity - i would guess to use this but there's not rad given.

Angular velocity can also be represented as;

\omega = \frac{v}{r}

Regards
-Hoot
 
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