"Span of a Subspace - Does it Equal x?

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Homework Statement



If x is a subspace of V so, span(x)=x

Homework Equations



span(x)=x


The Attempt at a Solution



If x is a subspace so, for any "a", "b" in x:
a+b∈x
and (c1)*a∈x

So a linear combination of x belongs to x but is equal to x?
 
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Your last sentence is badly worded. There is no such thing as "a linear combination of x". You mean "a linear combination of vectors in x".

What you have proved is only one direction- you have proved that the span of x is a subset of x. Now you need to prove that x is a subset of span of x. That is easy. Suppose a is vector in x. Then 1a is in the span of x.
 
Hi, thanks!
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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