Spanning Sets in Vector Spaces

mlb2358
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Homework Statement


True or False: If S is a spanning set for a vector space V, then every vector v in V must be uniquely expressible as a linear combination of the vectors in S.

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The Attempt at a Solution


For some reason, the answer to this question is false, although to me it seems like this is almost the definition of a spanning set. I am unsure about what the word "uniquely" means here, so maybe that is causing my confusion. Any help would be appreciated!
 
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I think you're onto it, but i'd go back to your definition of a spanning set. If it only requires that the set spans V and uniqueness is not required, then there may exist more than one way to form a given vector v, e.g. consider if your set had both (1,0,0) and (2,0,0) in it..
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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