Special Relativity and Decaying Particles

AI Thread Summary
The discussion centers on calculating the height of a cosmic-ray collision that created a pion, given its energy and decay properties. Participants explore the relationship between total energy, mass, and kinetic energy, emphasizing the significance of the Lorentz factor (γ) in special relativity. A participant initially miscalculates γ, leading to confusion in determining the pion's speed and decay height. After correcting a sign error in the energy equation, the correct value for γ is suggested to be 895, which aligns with the principles of special relativity. The conversation highlights the importance of accurate calculations in understanding particle behavior in high-energy physics.
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Homework Statement


Pions are part of a class of short-lived particles called mesons which commonly created during the collisions in scientific accelerators or when cosmic rays collide with particles in the upper part of the Earth's atmosphere. A type of pion known as a π+ has a mass of 139.6 MeV/c2. One particular π+ was created during a collision in the Earth's upper atmosphere and has an total energy E= 1.25 X 105 MeV. As measured in its own frame, it has a life time of 38 nsec before it decays.
a) If it decays at a point 146 meters above sea-level, how high above sea-level was the comsic-ray collision that created the pion?

hcollision = m
255345.052163 NO

HELP: Provide this information in the frame of reference of an observer on earth.
HELP: How are the total energy and mass of an object related?

b) How long does the particle live in the frame of reference of an observer on earth??
Δtearth = nsec

c) In the frame of reference of the pion, how far does it traveled before it decayed?
Δxπ = m *
11.39 OK

Homework Equations


d ' = dγ
γ = sqrt (1 - v^2/c^2)
E = K - mc^2
K = mc^2[(1/γ)-1]

The Attempt at a Solution


I used total energy + rest energy (E + mc^2) = kinetic energy (K). When I solved K for V I found that the particle was moving nearly at the speed of light. .999999999004c (that's 9 9s).

I used that speed to calculate my γ = 4.46318e-5.

d' = dγ
11.39m = d (4.46318e-5)
d = 255199.052163 m

The particle decayed 146m about sea level so d+146 = 255345.052163.

But it tells me no, so I believe the error might have come in calculating my V. If I can get A, B will be no problem...but I'm stuck.

Help! Thanks!
 
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You have a sign error in one of your equations. The total energy is the sum of the rest energy and the kinetic energy.

Your value for ##\gamma## can't possibly be correct since ##\gamma \ge 1##.
 
vela said:
You have a sign error in one of your equations. The total energy is the sum of the rest energy and the kinetic energy.

Your value for ##\gamma## can't possibly be correct since ##\gamma \ge 1##.

I corrected my sign error: E = k + mc^2. However, that doesn't really change anything. My energy is 1.25e5 and the 139.6 MeV of mass isn't making any appreciable change in my kinetic energy. I'm getting the same answer.
 
What are you getting for ##\gamma##? You should get ##\gamma=895##.
 
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