Denton
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Ive heard that length contraction does not occur when the movement of the object is perpendicular to the observer. Is this correct?
Say two identical rings were traveling at each other at relativistic speeds, whilst the observer is perpendicular to them. Ring A would see ring B contract and therefore pass through whereas ring B would see ring A contract and go through it. Since both can't contract AND pass through each other as seen by the perpendicular observer, it does not apply to perpendicular frames of reference.
Say two identical rings were traveling at each other at relativistic speeds, whilst the observer is perpendicular to them. Ring A would see ring B contract and therefore pass through whereas ring B would see ring A contract and go through it. Since both can't contract AND pass through each other as seen by the perpendicular observer, it does not apply to perpendicular frames of reference.