Special Relativity, please explain the meaning of this problem

[shanu_bhaiya]

Homework Statement
The reference frame K' moves in the positive direction of the x-axis of the frame K with a relative velocity V. Suppose that at the moment when the origins of coordinates O and O' coincide, the clock readings at these points are equal to zero in both frames. Find the displacement velocity v of the point (in the frame K) at which the readings of the clocks of both reference frames will be permanently identical. Demonstrate that v<V.

The meaning of the problem
Ok, the problem is that I don't understand the meaning of the problem. Does it mean to find the velocity of a point (v) such that the clocks infront of each other in that point's frame show same time, but that seems me impossible, if not then what the problem may mean.
I only want to know the meaning of the problem, please don't solve it.

Reference
Problem is 1.355 from "Problems in General Physics - I. E. Irodov". And answer is v = (1-(1-(V/c)²)^1/2)c²/V

 

[turin]

I think it means that you need to find the speed of an observer, relative to K, at which the observer would calculate the clock rates in K and K' to be the same.

 

[shanu_bhaiya]

Yup, thnx turin, that is what it meant.