Special Relativity: Time Dilation Prob

AI Thread Summary
The discussion revolves around a time dilation problem involving Bob, who travels at relativistic speeds to planet Bongo and back to Earth, while Sarah remains stationary. The initial calculations suggested that Sarah ages more than Bob during the journey, but after further analysis using a spacetime diagram, the conclusion shifted to Bob aging less than Sarah. The key equations used include the gamma factor for time dilation and the basic time calculation based on distance and velocity. The confusion stemmed from misapplying the principles of special relativity, but the final understanding confirmed that Sarah ages 2.35 years while Bob ages only 1.26 years. The thread highlights the complexities of applying special relativity to real-world scenarios.
ChrisJ
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It has been 2.5years since I last did any special relativity so am rather rusty on it, I have a simple time dilation problem and its making my head hurt which way around it should be. Any help much appreciated!

1. Homework Statement

Bob leaves Sarah on Earth and travels in a spaceship at 0.8c in a straight line to planet Bongo and then turns around and travels now at 0.9c back to Earth. To Sarah on Earth, planet Bongo is 1lyr away. Ignoring any acceleration effects, by how much have Bob and Sarah aged when Bob returns to Earth.

Homework Equations


##\gamma = \frac{1}{\sqrt{1-v^2/c^2}} ##
##\Delta t ' = \gamma \Delta t##

The Attempt at a Solution


[/B]
Originally, I had Sarah's frame as the rest frame, and therefore if traveling at 0.8c it should take 1/0.8=1.25 years to get to Bongo and 1/0.9=1.1 years to get back.

The gamma factor for the outbound journey is ##\gamma_o = \frac{1}{\sqrt{1-0.8^2}} = 1.6## and for the return journey is ##\gamma_r = \frac{1}{\sqrt{1-0.9^2}} = 2.29##

Without looking at the equations, or drawing a spacetime diagram, I reminded myself of the twin paradox and similar problems, that if one travels on a spaceship at close to light sped and returns, everyone on Earth is older than expected. Remembering this I thought, well that means

that for Bob it has been ##1.25+1.1=2.35## years whilst for Sarah its been ##(1.25)(1.6) + (1.1)(2.29) = 4.5 ##years

But then after drawing a space-time diagram, I think that was wrong and that it is actually that for Sarah it has been ##1.25+1.1=2.35## years whilst for Bob it has only been ##\frac{1.25}{1.6}+\frac{1.1}{2.39} = 1.26## years.

And now I am pretty certain its the latter, but am self doubting. As I said its been almost 3 years since I have I had to think about SR or done any SR problems. Any help is much appreicated.
 
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If you analyse the problem in Sarah's frame, then SR doesn't enter into her calculations. It's a simple ##t = d/v## problem!
 
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PeroK said:
If you analyse the problem in Sarah's frame, then SR doesn't enter into her calculations. It's a simple ##t = d/v## problem!

Yeah that is how I started, as you can see that is what I did to get the 1.25yrs and 1.1yrs, but then somehow I got confused. But I did realize my mistake and by the time I had finished writing this post was certain that my second attempt was correct, but as I spent the time to write it out I thought I may as well post it.
 
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