Specific gravity and pressure question

[sheababy33]

Homework Statement

a collapsible plastic bag contains a glucose solution. if the avg gauge pressure in the vein is 12300 pa, what must be the minimum height of the bag in order to infuse glucose into the vein? assume the specific gravity of the solution is 1.02. the acceleration of gravity is 9.8.
answer in units of m.

Homework Equations

d=m/v
p=HDa
f=pa

The Attempt at a Solution

i tried plugging in everything that i could into different equations but i can't get anything that seem right, i don't really understand specific gravity cause my teacher hasn't taught it to us.

 

[anathema]

Hello! I can help you solve this problem. Let's break it down step by step:

First, we need to understand the given information. The average gauge pressure in the vein is 12300 Pa. This means that the pressure exerted by the glucose solution in the bag must be equal to or greater than 12300 Pa in order for it to flow into the vein.

Next, we need to understand the concept of specific gravity. Specific gravity is the ratio of the density of a substance to the density of water. In this case, the specific gravity of the solution is 1.02. This means that the solution is slightly more dense than water.

Now, let's look at the equations you listed. The first one, d=m/v, is the equation for density. We can use this to find the density of the glucose solution. Since we know the specific gravity, which is the ratio of the density of the solution to the density of water, we can set up the following equation:

1.02 = ρ/1000

Where ρ is the density of the solution and 1000 is the density of water in kg/m^3. Solving for ρ, we get ρ = 1020 kg/m^3.

Next, we can use the equation p=HDa, where p is pressure, H is height, D is density, and a is acceleration due to gravity. We know the pressure (12300 Pa), density (1020 kg/m^3), and acceleration due to gravity (9.8 m/s^2). We can rearrange the equation to solve for H:

H = p/(Da)

Plugging in the values, we get:

H = 12300 Pa / (1020 kg/m^3 * 9.8 m/s^2) = 1.25 m

Therefore, the minimum height of the bag must be 1.25 m in order for the glucose solution to flow into the vein.

I hope this helps! Let me know if you have any further questions.