Specific heat (I'm not sure if it's capacity or latent)

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Homework Help Overview

The discussion revolves around a physics problem involving the specific heat capacity and latent heat of water. The original poster seeks assistance with calculating the time required to heat water in a kettle and the mass of water remaining after boiling for a specified duration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the assumptions made regarding energy loss and vapor escape. There is an exploration of the relationship between power, energy, and mass in the context of latent heat. Questions arise about the correct application of formulas and the interpretation of energy values.

Discussion Status

Some participants confirm the calculations for part (a) and provide guidance on the approach for part (b). There is an ongoing exploration of the energy values and their implications for the mass of steam produced, with no explicit consensus reached on the final answer.

Contextual Notes

Assumptions include no heat loss to the surroundings and that all vapor escapes the kettle. Participants express uncertainty about the energy values and their sources, indicating potential gaps in understanding.

gabloammar
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Homework Statement


Part a. A 500 W kettle contains 300g of water at 20°C. Calculate the time it would take to raise the temperature of the water to boiling point.

Part b. The kettle is allowed to boil for 2 minutes. Calculate the mass of water that would remain in the kettle.

State any assumptions you make.

(Specific heat capacity of water = 4.18x103 J kg-1 °C-1, specific latent heat of vaporisation of water = 2.26x106 J kg-1.)


2. The attempt at a solution
I have the answer for part a. It's (rounded) about 201 seconds.

Problem: I don't know where to start from for part b. Someone help.
 
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Oh and I'm making two assumptions.
1. There's no energy lost to the surroundings.
2. All the vapour formed escapes the kettle.
 
I agree with your time for part (a)
Once the water is boiling there is no increase in temperature ( boils at 100C) so all of the energy supplied ( in 2 minutes) is used to convert liquid water into water vapor ( steam)
The usual assumptions about no heat loss etc.
 
Yep yep I can think about that. Fine. But, the only formula I've got in my head is E=mL, and the only way I'm thinking of finding the energy change [E in the equation] is power equals work done by time taken. Using that, power being 500 W and time taken being 120 seconds, the work equals 60kJ [I'm not even sure if I should be doing that or not].

So I've got energy and I've got specific latent heat. What next? Put 'em in the formula?

mass equals energy by specific latent heat, and I get 37.7 [is this kg or grams?].

Seriously, I'm COMPLETELY at sea with this.
 
Oh btw the answer is supposed to be 273g, rounded off to 270g. No idea where it comes from though.
 
You are doing the right thing.
60kJ in 2 mins is correct so the mass of steam = ( 60 x 10^3)/2.26 x 10^6
which is 0.027 kg
(where did you get the answer to be 273g?)
 
Last edited:
I could've sworn I was doing the same thing over and over again and not getting that value! Or maybe I was looking at the energy in a wrong way [I have the value 59892.5 J written on the notebook, no clue where I got it from though]. But thanks! Question solved :D
 
great...don't you wish all problems were so easy:wink:
 
Of course :p
 

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